Delete a Node HackerRank Solution

Delete a Node HackerRank Solution
Source : https://www.hackerrank.com/challenges/delete-a-node-from-a-linked-list

_{This challenge is part of a tutorial track by MyCodeSchool and is accompanied by a video lesson.}

You’re given the pointer to the head node of a linked list and the position of a node to delete. Delete the node at the given position and return the head node. A position of 0 indicates head, a position of 1 indicates one node away from the head and so on. The list may become empty after you delete the node.

Input Format

You have to complete the deleteNode(SinglyLinkedListNode* llist, int position) method which takes two arguments - the head of the linked list and the position of the node to delete. You should NOT read any input from stdin/console. position will always be at least 0 and less than the number of the elements in the list.

The first line of input contains an integer , denoting the number of elements in the linked list.
The next lines contain an integer each in a new line, denoting the elements of the linked list in the order.
The last line contains an integer denoting the position of the node that has to be deleted form the linked list.

Constraints

• , where is the element of the linked list.

Output Format

Delete the node at the given position and return the head of the updated linked list. Do NOT print anything to stdout/console.

The code in the editor will print the updated linked list in a single line separated by spaces.

Sample Input

8206219741593

Sample Output

20 6 2 7 4 15 9

Explanation

The given linked list is 20->6->2->19->7->4->15->9. We have to delete the node at position 3, which is 19. After deleting that node, the updated linked list is: 20->6->2->7->4->15->9

Source : https://www.hackerrank.com/challenges/delete-a-node-from-a-linked-list

Solution

	// Karthikalapati.blogspot.com
	/*
	Delete Node at a given position in a linked list
	Node is defined as
	class Node {
	int data;
	Node next;
	}
	*/
	Node Delete(Node head, int position) {
	if (head == null) {
	return null;
	} else if (position == 0) {
	return head.next;
	} else {
	/* Get Node one element before desired position */
	Node n = head;
	for (int i = 0; i < position - 1; i++) {
	n = n.next;
	}
	/* Delete Node */
	n.next = n.next.next;
	return head;
	}
	}

Insert a node at a specific position in a linked list HackerRank Solution

Insert a node at a specific position in a linked list HackerRank Solution
Source : https://www.hackerrank.com/challenges/insert-a-node-at-a-specific-position-in-a-linked-list

_{This challenge is part of a tutorial track by MyCodeSchool and is accompanied by a video lesson.}

You’re given the pointer to the head node of a linked list, an integer to add to the list and the position at which the integer must be inserted. Create a new node with the given integer, insert this node at the desired position and return the head node.

A position of 0 indicates head, a position of 1 indicates one node away from the head and so on. The head pointer given may be null meaning that the initial list is empty.

As an example, if your list starts as and you want to insert a node at position with , your new list should be

Function DescriptionComplete the function insertNodeAtPosition in the editor below. It must return a reference to the head node of your finished list.

insertNodeAtPosition has the following parameters:

• head: a SinglyLinkedListNode pointer to the head of the list
• data: an integer value to insert as data in your new node
• position: an integer position to insert the new node, zero based indexing

Input Format

The first line contains an integer , the number of elements in the linked list.
Each of the next lines contains an integer SinglyLinkedListNode[i].data.
The next line contains an integer denoting the data of the node that is to be inserted.
The last line contains an integer .

Constraints

• , where is the element of the linked list.
• .

Output Format

Return a reference to the list head. Locked code prints the list for you.

Sample Input

31613712

Sample Output

16 13 1 7

Explanation

The initial linked list is 16 13 7. We have to insert at the position which currently has in it. The updated linked list will be 16 13 1 7

Source : https://www.hackerrank.com/challenges/insert-a-node-at-a-specific-position-in-a-linked-list

Solution

	// Karthikalapati.blogspot.com
	/*
	Insert Node at a given position in a linked list
	First element in the linked list is at position 0
	Node is defined as
	class Node {
	int data;
	Node next;
	}
	*/
	Node InsertNth(Node head, int data, int position) {
	Node newNode = new Node();
	newNode.data = data;
	if (position == 0) {
	newNode.next = head;
	return newNode;
	} else {
	/* Get Node one element before desired position */
	Node n = head;
	for (int i = 0; i < position - 1; i++) {
	n = n.next;
	}
	/* Insert our new Node */
	newNode.next = n.next;
	n.next = newNode;
	return head;
	}
	}