Most Important Frequently Asked Agilent Technologies Aptitude Interview Questions
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Answer :
Total Distance to be travelled by both the trains = 130 + 110 = 240m
Let ‘F ’and ‘S’ be the speeds of fast and slow trains in m/sec. 240=60(F-S), 240= (F+S)
In the same direction, F – S = 4 m/sec …… (1)
In the opposite direction, F + S =80 m/sec…… (2)
Solving them we get F = 42 m/sec.
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Answer :
Given, speed of the Boat in still water (B) =10 km/hr
Let S be the speed of flow of river, then
91/(10+S) + 91/(10-S) = 20, Then going by options
91/13 - 91/7 = 20
So, S = 3 km/hr.
Aptitude Interview Questions -
Answer :
Total tractor population = 2, 94,000
Mahindra & Mahindra = 1, 50,000
So, Non Mahindra trucks = 1, 44,000
Since out of every 1000 Mahindra tractors, 98 are red, out of 1, 50,000 Mahindra tractors 14,700 are red.
5.3% of 2, 94,000 = 15,582 are red tractors in all.
So non Mahindra tractors which are red =15,582 – 14,700 = 882
Hence percentage of non Mahindra tractors that are red = 882/144,000 * 100 = 0.6125%
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Answer :
Difference in % of wheat lost = 7 – 26/5 = 9/5%
Difference in import = 12 – 3 = 9 million as 9/5% % of total qty of wheat = 9 million
⇒ 9x/500 = 9
⇒ x = 500 million
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Answer :
Try option & get answer as fourth option:
(200/(48 - 32)) - (200/ (48 + 32)) (12(1/2) min - 2(1/2) min)
= 10 min
Wipro Technical Interview Questions -
Answer :
Total no. of round will be 5000/400 = 12.5
No. of rounds A completes to finish the race will be 12.5 and by the time B can complete only 10 rounds.
(As ratio of speed of A & B is 5: 4. So they meet for the first time after A has finished 5 rounds and B has finished 4 rounds.)
So difference in no. of round will be = 21⁄2
The winner meets the other 2 times because the winner meets the other after every 2000 meters.
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Answer :
Let total income be = 5
Increased income will be = 5.5
Increased expenditure will be = 3.36
Increased saving will be = 5.5 – 3.36 = 2.14
Percentage increase will be = 14/2 * 100 = 7%
IGate Technical Interview Questions -
Answer :
Some of areas of 2 smaller parks = New bigger one
π (8)² + π(6)² = πr²
π [64+36] = πr²
π *100 = πr²
r= 10
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Answer :
Area of Pond = 64
Area of field = 64 × 8 = 512
Area of field ⇒ x. 2x = 512
⇒ 2x2 = 512 ⇒ x2 = 256 ⇒ x = 16
Length = 2 × 16 = 32.
ABB Group Aptitude Interview Questions -
Answer :
A & B one day work = 1/8
A alone one day work = 1/12
B alone one day work = (1/8 - 1/12) = ( 3/24 - 2/24)
=> B one day work = 1/24
So B can complete the work in 24 days.
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Answer :
Let's the number of pages typed in one hour by P, Q and R be p, q and r respectively. Then,
P,Q and R typed page in 1 hrs = 216/4
=> p + q + r = 216/4
=> p + q + r = 54 ... (i)
r - q = q - p => 2p = q + r ...(ii)
5r = 7p => p = 5/7 r ... (iii)
By Solving above (i), (ii) and (iii) equations
=> p = 15, q = 18, q = 21
Abaxis Aptitude Interview Questions -
Answer :
(A and B) 1 day work = 1/12 -----(1)
(B and C) 1 day work = 1/16 -----(2)
Given A's 5 days' work + B's 7 days' work + C's 13 days' work = 1
Simplify the above...
=> (A + B)'s 5 days' work + (B + C)'s 2 days' work + C's 11 days' work = 1
Put the values from equation (1) & (2)
=> (5*1/12)+(2*1/16) + C's 11 days' work = 1
=> C's 11 days' work = (1-5/12+2/16)=11/24
=> C's 1 day's work = (11/24? 1/11) =1/24
So C alone can finish the work = 24 days.
Aptitude Interview Questions -
Answer :
A's 1 day work = 1/45
B's 1 day work = 1/40
so (A + B)'s 1 day's work = (1/45+1/40)=17/360
Work done by B in 23 days = (140? 23) =2340
Remaining work = (1-23/40) =17/40
Now, 17/360 work was done by (A + B) = 1 day.
17/40 part of work was done by (A + B) = (1? 360/17? 17/40) = 9 days.
A left after 9 days.
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Answer :
B's daily earning = Rs. (300 - 188) = Rs. 112.
A's daily earning = Rs. (300 - 152) = Rs. 148.
C's daily earning = Rs. [300 - (112 + 148)] = Rs. 40.
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Answer :
Find the 1 day work for all three
1 day's work for all three = (1/15 + 1/20 + 1/25)
= (20/300 + 15/300 + 12/300) = 47/300
So all together can do the work in 300/47 days. => 6.4 days.
Apple Technical Interview Questions -
Question 16. 287 X 287 + 269 X 269 - 2 X 287 X 269 =?
Answer :
Given Exp. = a2 + b2 - 2ab, where a = 287 and b = 269
= (a - b)2 = (287 - 269)2
= (182)
= 324
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Answer :
Let’s assume three workers a a,b and c
Their average salary is (a+b+c)/3 = 95
=> a+b+c=285
a=115,
b=65
So c=285-115-65=105
Infosys Aptitude Interview Questions -
Answer :
Required average
=> (510 * 5 + 240 * 25)/30.
=> 8550/30
=> 285.
Wipro Technical Interview Questions -
Question 19. How Much Is 80% Of 40 Is Greater Than 4/5 Of 25?
Answer :
0% of 40 = 40 * (80/100) and 4/5 of 25 = 25 * 4/5
[40* (80/100) - 25*(4/5)] = [3200/100 - 100/5]
= 32 - 20
= 12.
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Answer :
CP* (76/100) = 912 => CP = 912 * 100/76
CP= 12 * 100
=> CP = 1200
Cost price of article = Rs. 1200
Topic: Agilent Technologies Aptitude Interview Questions
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