AGILENT TECHNOLOGIES APTITUDE INTERVIEW QUESTIONS

Most Important Frequently Asked Agilent Technologies Aptitude Interview Questions

1. Question 1. Two Trains 130 And 110 Meters Long Are Going In The Same Direction. The Faster Train Takes One Minute To Pass The Other Completely. If They Are Moving In Opposite Directions, They Pass Each Other Completely In 3 Seconds. Find The Speed Of The Faster Train?

   Answer :

   Total Distance to be travelled by both the trains = 130 + 110 = 240m

   Let ‘F ’and ‘S’ be the speeds of fast and slow trains in m/sec. 240=60(F-S), 240= (F+S)

   In the same direction, F – S = 4 m/sec …… (1)

   In the opposite direction, F + S =80 m/sec…… (2)

   Solving them we get F = 42 m/sec.

2. Question 2. A Motor Boat Can Travel At 10 Km/h In Still Water. It Travelled 91 Km Downstream In A River And Then Returned, Taking Altogether 20 Hours. Find The Rate Of Flow Of The River?

   Answer :

   Given, speed of the Boat in still water (B) =10 km/hr

   Let S be the speed of flow of river, then

   91/(10+S) + 91/(10-S) = 20, Then going by options

   91/13 - 91/7 = 20

   So, S = 3 km/hr.

Aptitude Interview Questions

3. Question 3. The Total Tractor Population In A State Is 2, 94,000, Out Of Which 1, 50,000 Are Made By Mahindra & Mahindra. Out Of Every 1,000 Mahindra Tractors, 98 Are Red In Colour, But Only 5.3% Of The Total Tractor Population Is Red. Find The Percentage Of Non-mahindra Tractors That Are Red?

   Answer :

   Total tractor population = 2, 94,000

   Mahindra & Mahindra = 1, 50,000

   So, Non Mahindra trucks = 1, 44,000

   Since out of every 1000 Mahindra tractors, 98 are red, out of 1, 50,000 Mahindra tractors 14,700 are red.

   5.3% of 2, 94,000 = 15,582 are red tractors in all.

   So non Mahindra tractors which are red =15,582 – 14,700 = 882

   Hence percentage of non Mahindra tractors that are red = 882/144,000 * 100 = 0.6125%

4. Question 4. 7% Of The Total Quantity Of Wheat Is Lost In Grinding When A Country Has To Import 12 Million Tones, But When Only 51⁄5 Is Lost, It Can Import 3 Million Tones. Find The Quantity Of Wheat Grown In The Country?

   Answer :

   Difference in % of wheat lost = 7 – 26/5 = 9/5%

   Difference in import = 12 – 3 = 9 million as 9/5% % of total qty of wheat = 9 million

   ⇒ 9x/500 = 9

   ⇒ x = 500 million

5. Question 5. A Man Who Can Swim 48 M/min In Still Water Swims 200m Against The Current And 200 M With The Current. If The Difference Between Those 2 Times Is 10 Minutes, Find The Speed Of The Current?

   Answer :

   Try option & get answer as fourth option:

   (200/(48 - 32)) - (200/ (48 + 32)) (12(1/2) min - 2(1/2) min)

   = 10 min

Wipro Technical Interview Questions

6. Question 6. A And B Run A 5 Km Race On A Round Course Of 400 M. If Their Speed Be In The Ratio 5 : 4, How Often Does The Winner Pass The Other On Circular Track?

   Answer :

   Total no. of round will be 5000/400 = 12.5

   No. of rounds A completes to finish the race will be 12.5 and by the time B can complete only 10 rounds.

   (As ratio of speed of A & B is 5: 4. So they meet for the first time after A has finished 5 rounds and B has finished 4 rounds.)

   So difference in no. of round will be = 21⁄2

   The winner meets the other 2 times because the winner meets the other after every 2000 meters.

7. Question 7. Mira’s Expenditure And Saving Are In The Ratio 3:2. Her Income Increases By 10%. Her Expenditure Also Increases By 12%. By How Much % Do Her Saving Increase?

   Answer :

   Let total income be = 5

   Increased income will be = 5.5

   Increased expenditure will be = 3.36

   Increased saving will be = 5.5 – 3.36 = 2.14

   Percentage increase will be = 14/2 * 100 = 7%

IGate Technical Interview Questions

8. Question 8. Two Small Circular Parks Of Diameters 16 M, 12 M Are To Be Replaced By A Bigger Circular Park. What Would Be The Radius Of This New Park, If The New Park Occupies The Same Space As The Two Small Parks?

   Answer :

   Some of areas of 2 smaller parks = New bigger one

   π (8)² + π(6)² = πr²

   π [64+36] = πr²

   π *100 = πr²

   r= 10

9. Question 9. The Length Of A Rectangular Field Is Double Its Width, Inside The Field There Is A Square-shaped Pond 8 M Long. If The Area Of The Pond Is 1/8 Of The Field, What Is The Length Of The Field?

   Answer :

   Area of Pond = 64

   Area of field = 64 × 8 = 512

   Area of field ⇒ x. 2x = 512

   ⇒ 2x2 = 512 ⇒ x2 = 256 ⇒ x = 16

   Length = 2 × 16 = 32.

ABB Group Aptitude Interview Questions

10. Question 10. A' And 'b' Complete A Work Together In 8 Days. If 'an' Alone Can Do It In 12 Days. Then How Many Day 'b' Will Take To Complete The Work?

    Answer :

    A & B one day work = 1/8 

    A alone one day work = 1/12

    B alone one day work = (1/8 - 1/12) = ( 3/24 - 2/24) 

    => B one day work = 1/24

    So B can complete the work in 24 days.

11. Question 11. P, Q And R Are Three Typists Who Working Simultaneously Can Type 216 Pages In 4 Hours. In One Hour, R Can Type As Many Pages More Than Q As Q Can Type More Than P. During A Period Of Five Hours, R Can Type As Many Pages As P Can During Seven Hours. How Many Pages Does Each Of Them Type Per Hour?

    Answer :

    Let's the number of pages typed in one hour by P, Q and R be p, q and r respectively. Then,

    P,Q and R typed page in 1 hrs = 216/4

    => p + q + r = 216/4

    => p + q + r = 54 ... (i)

    r - q = q - p => 2p = q + r ...(ii)

    5r = 7p => p = 5/7 r ... (iii)

    By Solving above (i), (ii) and (iii) equations

    => p = 15, q = 18, q = 21

Abaxis Aptitude Interview Questions

12. Question 12. A And B Together Can Do A Piece Of Work In 12 Days, Which B And C Together Can Do In 16 Days. After A Has Been Working At It For 5 Days And B For 7 Days, C Finishes It In 13 Days. In How Many Days C Alone Will Do The Work?

    Answer :

    (A and B) 1 day work = 1/12 -----(1)

    (B and C) 1 day work = 1/16 -----(2)

    Given A's 5 days' work + B's 7 days' work + C's 13 days' work = 1

    Simplify the above...

    => (A + B)'s 5 days' work + (B + C)'s 2 days' work + C's 11 days' work = 1

    Put the values from equation (1) & (2)

    => (5*1/12)+(2*1/16) + C's 11 days' work = 1

    => C's 11 days' work = (1-5/12+2/16)=11/24

    => C's 1 day's work = (11/24? 1/11) =1/24

    So C alone can finish the work = 24 days.

Aptitude Interview Questions

13. Question 13. A And B Can Do A Piece Of Work In 45 Days And 40 Days Respectively. They Began To Do The Work Together But A Leaves After Some Days And Then B Completed The Remaining Work In 23 Days. The Number Of Days After Which A Left The Work Was?

    Answer :

    A's 1 day work = 1/45

    B's 1 day work = 1/40

    so (A + B)'s 1 day's work = (1/45+1/40)=17/360

    Work done by B in 23 days = (140? 23) =2340

    Remaining work = (1-23/40) =17/40

    Now, 17/360 work was done by (A + B) = 1 day.

    17/40 part of work was done by (A + B) = (1? 360/17? 17/40) = 9 days.

    A left after 9 days.

14. Question 14. A, B And C Together Earn Rs. 300 Per Day, While A And C Together Earn Rs. 188 And B And C Together Earn Rs. 152. The Daily Earning Of C Is?

    Answer :

    B's daily earning = Rs. (300 - 188) = Rs. 112.

    A's daily earning = Rs. (300 - 152) = Rs. 148.

    C's daily earning = Rs. [300 - (112 + 148)] = Rs. 40.

15. Question 15. A Man Can Do A Job In 15 Days. His Father Takes 20 Days And His Son Finishes It In 25 Days. How Long Will They Take To Complete The Job If They All Work Together?

    Answer :

    Find the 1 day work for all three 

    1 day's work for all three = (1/15 + 1/20 + 1/25)

    = (20/300 + 15/300 + 12/300) = 47/300

    So all together can do the work in 300/47 days. => 6.4 days.

Apple Technical Interview Questions

16. Question 16. 287 X 287 + 269 X 269 - 2 X 287 X 269 =?

    Answer :

    Given Exp. = a^₂ + b^₂ - 2ab, where a = 287 and b = 269

    = (a - b)^₂ = (287 - 269)^₂

    = (182)

    = 324

17. Question 17. The Average Salary Of 3 Workers Is 95 Rs. Per Week. If One Earns Rs.115 And Second Earns Rs.65 How Much Is The Salary Of The 3rd Worker?

    Answer :

    Let’s assume three workers a a,b and c

    Their average salary is (a+b+c)/3 = 95

    => a+b+c=285

    a=115, 

    b=65 

    So c=285-115-65=105

Infosys Aptitude Interview Questions

18. Question 18. A Library Has An Average Of 510 Visitors On Sundays And 240 On Other Days. The Average Number Of Visitors Per Day In A Month Of 30 Days Beginning With A Sunday Is?

    Answer :

    Required average

    => (510 * 5 + 240 * 25)/30.

    => 8550/30

    => 285.

Wipro Technical Interview Questions

19. Question 19. How Much Is 80% Of 40 Is Greater Than 4/5 Of 25?

    Answer :

    0% of 40 = 40 * (80/100) and 4/5 of 25 = 25 * 4/5

    [40* (80/100) - 25*(4/5)] = [3200/100 - 100/5]

    = 32 - 20

    = 12.

20. Question 20. After Decreasing 24% In The Cost Price Of An Article, Its Costs Rs.912. Find The Actual Cost Of An Article?

    Answer :

    CP* (76/100) = 912 => CP = 912 * 100/76

    CP= 12 * 100 

    => CP = 1200

    Cost price of article = Rs. 1200

Topic: Agilent Technologies Aptitude Interview Questions