Source : https://www.hackerrank.com/challenges/ctci-bubble-sort
Consider the following version of Bubble Sort:
for (int i = 0; i < n; i++) { for (int j = 0; j < n - 1; j++) { // Swap adjacent elements if they are in decreasing order if (a[j] > a[j + 1]) { swap(a[j], a[j + 1]); } } }
Given an array of integers, sort the array in ascending order using the Bubble Sort algorithm above. Once sorted, print the following three lines:
Array is sorted in numSwaps swaps.
, where is the number of swaps that took place.First Element: firstElement
, where is the first element in the sorted array.Last Element: lastElement
, where is the last element in the sorted array.
Hint: To complete this challenge, you must add a variable that keeps a running tally of all swaps that occur during execution.
For example, given a worst-case but small array to sort: we go through the following steps:
swap a 0 [6,4,1]1 [4,6,1]2 [4,1,6]3 [1,4,6]
It took swaps to sort the array. Output would be
Array is sorted in 3 swaps. First Element: 1 Last Element: 6
Function Description
Complete the function countSwaps in the editor below. It should print the three lines required, then return.
countSwaps has the following parameter(s):
- a: an array of integers .
Input Format
The first line contains an integer, , the size of the array .
The second line contains space-separated integers .
Constraints
Output Format
You must print the following three lines of output:
Array is sorted in numSwaps swaps.
, where is the number of swaps that took place.First Element: firstElement
, where is the first element in the sorted array.Last Element: lastElement
, where is the last element in the sorted array.
Sample Input 0
31 2 3
Sample Output 0
Array is sorted in 0 swaps.First Element: 1Last Element: 3
Explanation 0
The array is already sorted, so swaps take place and we print the necessary three lines of output shown above.
Sample Input 1
33 2 1
Sample Output 1
Array is sorted in 3 swaps.First Element: 1Last Element: 3
Explanation 1
The array is not sorted, and its initial values are: . The following swaps take place:
At this point the array is sorted and we print the necessary three lines of output shown above.
Source : https://www.hackerrank.com/challenges/ctci-bubble-sort
Solution
// Karthikalapati.blogspot.com | |
import java.util.Scanner; | |
public class Solution { | |
private static int swaps = 0; | |
public static void main(String[] args) { | |
/* Save input */ | |
Scanner scan = new Scanner(System.in); | |
int size = scan.nextInt(); | |
int [] array = new int[size]; | |
for (int i = 0; i < size; i++) { | |
array[i] = scan.nextInt(); | |
} | |
scan.close(); | |
bubbleSort(array); | |
System.out.println("Array is sorted in " + swaps + " swaps."); | |
System.out.println("First Element: " + array[0]); | |
System.out.println("Last Element: " + array[array.length - 1]); | |
} | |
private static void bubbleSort(int [] array) { | |
if (array == null) { | |
return; | |
} | |
boolean swapped = true; | |
int endOffset = 0; // optimizes code | |
while (swapped) { | |
swapped = false; | |
for (int i = 1; i < array.length - endOffset; i++) { | |
if (array[i-1] > array[i]){ | |
swap(array, i-1, i); | |
swapped = true; | |
} | |
} | |
endOffset++; | |
} | |
} | |
/* Standard swap. Also updates our "swaps" variable */ | |
private static void swap(int [] array, int i, int j) { | |
int temp = array[i]; | |
array[i] = array[j]; | |
array[j] = temp; | |
swaps++; | |
} | |
} |
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