Source : https://www.hackerrank.com/challenges/balanced-brackets
A bracket is considered to be any one of the following characters: (
, )
, {
, }
, [
, or ]
.
Two brackets are considered to be a matched pair if the an opening bracket (i.e., (
, [
, or {
) occurs to the left of a closing bracket (i.e., )
, ]
, or }
) of the exact same type. There are three types of matched pairs of brackets: []
, {}
, and ()
.
A matching pair of brackets is not balanced if the set of brackets it encloses are not matched. For example, {[(])}
is not balanced because the contents in between {
and }
are not balanced. The pair of square brackets encloses a single, unbalanced opening bracket, (
, and the pair of parentheses encloses a single, unbalanced closing square bracket, ]
.
By this logic, we say a sequence of brackets is balanced if the following conditions are met:
- It contains no unmatched brackets.
- The subset of brackets enclosed within the confines of a matched pair of brackets is also a matched pair of brackets.
Given strings of brackets, determine whether each sequence of brackets is balanced. If a string is balanced, return YES
. Otherwise, return NO
.
Function Description
Complete the function isBalanced in the editor below. It must return a string: YES
if the sequence is balanced or NO
if it is not.
isBalanced has the following parameter(s):
- s: a string of brackets
Input Format
The first line contains a single integer , the number of strings.
Each of the next lines contains a single string , a sequence of brackets.
Constraints
- , where is the length of the sequence.
- All chracters in the sequences ∈ { {, }, (, ), [, ] }.
Output Format
For each string, return YES
or NO
.
Sample Input
3{[()]}{[(])}{{[[(())]]}}
Sample Output
YESNOYES
Explanation
- The string
{[()]}
meets both criteria for being a balanced string, so we printYES
on a new line. - The string
{[(])}
is not balanced because the brackets enclosed by the matched pair{
and}
are not balanced:[(])
. - The string
{{[[(())]]}}
meets both criteria for being a balanced string, so we printYES
on a new line.
Source : https://www.hackerrank.com/challenges/balanced-brackets
Solution
// Karthikalapati.blogspot.com | |
import java.util.Scanner; | |
import java.util.HashMap; | |
import java.util.ArrayDeque; | |
// ArrayDeque is "likely to be faster than Stack when used as a stack" - Java documentation | |
// Time Complexity: O(n) | |
// Space Complexity: O(n) | |
public class Solution { | |
public static void main(String[] args) { | |
/* Create HashMap to match opening brackets with closing brackets */ | |
HashMap<Character, Character> map = new HashMap(); | |
map.put('(', ')'); | |
map.put('[', ']'); | |
map.put('{', '}'); | |
/* Test each expression for validity */ | |
Scanner scan = new Scanner(System.in); | |
int t = scan.nextInt(); | |
while (t-- > 0) { | |
String expression = scan.next(); | |
System.out.println(isBalanced(expression, map) ? "YES" : "NO" ); | |
} | |
scan.close(); | |
} | |
private static boolean isBalanced(String expression, HashMap<Character, Character> map) { | |
if ((expression.length() % 2) != 0) { | |
return false; // odd length Strings are not balanced | |
} | |
ArrayDeque<Character> deque = new ArrayDeque(); // use deque as a stack | |
for (int i = 0; i < expression.length(); i++) { | |
Character ch = expression.charAt(i); | |
if (map.containsKey(ch)) { | |
deque.push(ch); | |
} else if (deque.isEmpty() || ch != map.get(deque.pop())) { | |
return false; | |
} | |
} | |
return deque.isEmpty(); | |
} | |
} |
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