Balanced Brackets HackerRank Solution


Balanced Brackets HackerRank Solution
Source : https://www.hackerrank.com/challenges/balanced-brackets



Source : https://www.hackerrank.com/challenges/balanced-brackets


Solution


// Karthikalapati.blogspot.com
import java.util.Scanner;
import java.util.HashMap;
import java.util.ArrayDeque;
// ArrayDeque is "likely to be faster than Stack when used as a stack" - Java documentation
// Time Complexity: O(n)
// Space Complexity: O(n)
public class Solution {
public static void main(String[] args) {
/* Create HashMap to match opening brackets with closing brackets */
HashMap<Character, Character> map = new HashMap();
map.put('(', ')');
map.put('[', ']');
map.put('{', '}');
/* Test each expression for validity */
Scanner scan = new Scanner(System.in);
int t = scan.nextInt();
while (t-- > 0) {
String expression = scan.next();
System.out.println(isBalanced(expression, map) ? "YES" : "NO" );
}
scan.close();
}
private static boolean isBalanced(String expression, HashMap<Character, Character> map) {
if ((expression.length() % 2) != 0) {
return false; // odd length Strings are not balanced
}
ArrayDeque<Character> deque = new ArrayDeque(); // use deque as a stack
for (int i = 0; i < expression.length(); i++) {
Character ch = expression.charAt(i);
if (map.containsKey(ch)) {
deque.push(ch);
} else if (deque.isEmpty() || ch != map.get(deque.pop())) {
return false;
}
}
return deque.isEmpty();
}
}

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