Most Important Frequently Asked Bhel Aptitude Interview Questions
Interview Quesions on Bhel Aptitude
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Answer :
Given that time taken for riding both ways will be 2 hours lesser than the time needed for waking one way and riding back.
From this, we can understand that time needed for riding one way = time needed for waking one way - 2 hours.
Given that time taken in walking one way and riding back = 5 hours 45 min
Hence the time he would take to walk both ways = 5 hours 45 min + 2 hours = 7 hours 45 min.
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Answer :
Speed of the bus excluding stoppages = 54 kmph.
Speed of the bus including stoppages = 45 kmph.
Loss in speed when including stoppages = 54 - 45 = 9kmph.
=> In 1 hour, bus covers 9 km less due to stoppages
Hence, time that the bus stop per hour = time taken to cover 9 km.
=distance / speed= 9 / 54 hour = 1/6 hour = 60/6 min=10 min.
Electrical and Electronics Engineering Interview Questions -
Answer :
At the time of meeting, let the distance traveled by the first train be x km.
Then, distance covered by the second train is (x + 70) km.
=> x/60 = (x + 70)/75.
=> 75x = 60x + 60*70.
=> 15x = 4200 = x = 280 km.
So, distance between A and B = (x + x + 70)
= 280 + 280 + 70
= 630 km.
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Answer :
Let the cost price of 1 article be z.
So, the cost price of 20 article = 20z ------------------------- (1)
Selling Price of 20 articles = 20z + 25% of 20z = 25z
=> Selling Price of 1 article = 25z/20 = (5/4) *z
=> Selling Price of x articles = (5/4) *z*x ------------------------- (2)
Given that Selling Price (S.P.) of x articles = Cost Price (C.P.) of 20 articles
=> (5/4) *z*x = 20z
=> x = 16.
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Question 5. If Selling Price Is Doubled, The Profit Triples. Find The Profit Percent?
Answer :
Let the C.P. be x and the S.P. be y
So the profit is (y - x) ---------------------------- (1)
Now, the S.P. is doubled. So the new S.P. = 2y
The new profit = (2y - x)
Given that when S.P. is doubled, profit increases 3 times
=> New profit = 3 * old profit
=> (2y - x) = 3(y - x)
=> y = 2x
So, the profit = (y - x) = (2x - x) = x
% profit = (x / x) * 100 % = 100%.
Aptitude Interview Questions -
Answer :
Let the C.P. of the plot = Rs. x.
Given that x - 15% of x = 18700.
=> (85/100) * x = 18700.
=> x = 22000.
So the cost price (C.P.) of the plot = Rs. 22000.
S.P. of plot for 15% profit = 22000 + 15% of 22000 = 22000*(115/100) = 25300.
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Answer :
A completes the work in 6 days.
So, Work done by A in 1 day = 1/6.
=> A's 3-day work = 3/6 = 1/2.
B completes the work in 8 days
So, Work done by B in 1 day = 1/8
=> B's 3-day work = 3/8
The remaining work is done by C.
So the part of work done by C = 1 - (1/2+ 3/8) = 1/8.
So, C's share is 18 of 3200 = 3200 * 1/8 = 400.
Electrical Engineering Interview Questions -
Answer :
Let B takes x days to complete the job.
Since A is 3 times better than B, A takes one third of the time taken by B.
So, A can finish the job in x/3 days.
Given that time taken by A to complete the work is 60 days less than that of B
So, x/3 = x - 60.
=> x = 90.
So, B does the job in 90 days and A does in (90-60) days = 30 days.
Fraction of job done by A in 1 day = 1/30 and fraction of job done by B in 1 day = 1/90.
When working together, work done by A and B in 1 day = 1/30 + 1/90 = 2/45.
So, total time taken by A and B to complete the work together = 45/2.
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Answer :
Work done by A in 1 day = 1/16
Work done by B in 1 day = 1/12
Let C takes x days to lay railway track between two given stations.
So work done by C in 1 day = 1/x
A, B and C together take 4 days to lay the railway track.
So, in 1 day they complete 14 of the total work together
So, 1/16 + 1/12 + 1/x = 1/4
=> 1/x = 1/4 - 1/16 - 1/12
=> 1/x = 5/48
=> x = 48/5.
BHEL Interview Questions -
Answer :
Let the speed of the train be x km/hr.
Given, Speed of the man = 5 km/hr.
Since both the train and man are moving in the same direction so the speed of the train (relative to man) would be (x-5) km/hr.
Length of the train = 125 m = 125/1000 km = 18 km
Time taken to cross the man = 10 sec = 10/3600 hrs. = 1/360 hrs.
So speed =distance/time.
=> x-5 =360/ 8.
=> 8x - 40 = 360.
=> 8x = 400.
=> x = 50 km/hr.
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Answer :
Let the speeds of the two trains be a m/sec and b m/sec respectively.
Then, length of the first train = 27a meters,
and length of the second train = 17b meters.
so time = distance/ speed.
=> 23 = (27a+17b) / (a+b).
=> 23a + 23b = 27a +17b
=> 23a - 27a = 17b - 23b
=> -4 a = -6 b
=> 2 a = 3 b
=> a/ b= 3/2.
Electrician Assistant Interview Questions -
Answer :
The word JUDGE has 5 different letters.
When, the vowels UE are always together, they can be supposed to form one letter.
Then, we have to arrange the letters JDG (UE).
Now, 4 letters can be arranged in 4! = 24 ways.
The vowels (UE) can be arranged in 2! = 2 ways.
Required number of ways = (24 x 2) = 48.
Electrical and Electronics Engineering Interview Questions -
Answer :
'LOGARITHMS' contains 10 different letters.
Required number of words = Number of arrangements of 10 letters, taking 4 at a time.
‹=› 10p4
‹=› (10 x 9 x 8 x 7)
‹=› 5040.
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Answer :
Required numbers = (L.C.M of 12, 16, 18, 21, 28) + 7
‹=›1008 + 7
= 1015.
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Answer :
Other number = (11×7700 / 275)
= 308.
Electrical Power System Interview Questions -
Answer :
Let the numbers be x and (22 - x).
Then, 5x = 6(22 - x)
‹=› 11 x = 132
x = 12.
So, the numbers are 12 and 10.
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Answer :
Let the numbers be x and y.
Then, x + y = 20 and x - y = 8.
Therefore, x2 - y2 = (x + y)(x - y)
‹=› 20 x 8
‹=› 160.
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Answer :
Speed of the train = (30 x 5/18) m/sec
= (25 / 3) m/sec.
Distance moved in passing the standing man = 100 m.
Required time taken = 100 / (25 / 3)
= (100 x 3 / 25) sec
= 12 sec.
Aptitude Interview Questions -
Answer :
Relative Speed = (280 / 9) m/sec
= (280/9 x 18/5)
= 112 kmph.
Speed of the train = (112 - 50) kmph
= 62 kmph.
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Answer :
y = 125 + 10% of 125
= 125 + 12.50
= 137.50.
x = 137.50 - 10% of 137.50
= 137.50 - 13.75
= 123.75.
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Answer :
Let the number of students appeared be x.
Then, 65% of x = 455
‹=›65 / 100 x = 455
‹=› x= [455 x 100 / 65]
= 700.
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Answer :
Part filled by (A+B+C) in 1 hour = (1/5 + 1/6 + 1/30)
‹=› 1/3.
All the three pipes together will fill the tank in 3 hours.
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Answer :
Work done by the leak in 1 hour = (1/2 - 3/7)
‹=›1/14.
Leak will empty the tank in 14 hours.
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Answer :
P (getting a prize) = 10 / (10+25)
‹=› 10 / 35
‹=› 2 / 7.
Electrical Engineering Interview Questions -
Question 25. A Woodentoy Is Bought For Rs. 56000 And Sold At Profit Of 25 %. Find Its Selling Price?
Answer :
Cost price = Rs. 56000
Profit % = 25 %
Selling price = [(100 + Gain %)/100] * Cost price
Selling price = (125 /100) x 56000
Selling price = 70,000.
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Answer :
Required ratio = (6x1x1 / 6x5x5)
‹=›1/ 25
‹=›1: 125.
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Answer :
Surface area = (34398 / 13)
‹=›2646cm3
‹=›6a2= 2646
‹=›a2= 441
‹=›a = 21.
So, volume = (21x21x21) cm3= 9261cm3.
BHEL Interview Questions -
Answer :
Let the rate be R% p.a.
Then, (5000xRx2/100) + (3000xRx4/100)
‹=›100R+120R= 2200
‹=›R= (2200/220)
Rate ‹=›10%.
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Answer :
Let the capital be Rs. x.
Then, = (x × 8×1/100) - (x × 31/4×1/100)
= 61.50.
‹=›32x - 31x =6150×4
‹=›x= 24600.
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Answer :
Let the number of boys = x.
Then, number of girls = x.
Now, 2(x - 8) = x.
x = 16.
Total number of students = 2x = 2 x16 = 32.
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Answer :
N X 50 = (325000 - 300000) = 25000
N = 25000 / 50
= 500.
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Question 32. The Cube Root Of .000216 Is?
Answer :
(.000216)1/3 = (216 / 106)1/3
= (6 x 6 x / 102 x 102 x 102)1/3
= 6 / 102
= 6 / 100
= .06
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Question 33. The Largest Four Digit Number Which Is A Perfect Cube, Is?
Answer :
Clearly, 9261 is a perfect cube satisfying the given property.
Electrician Assistant Interview Questions
Topic: Bhel Aptitude Interview Questions
Interview Quesions on Bhel Aptitude
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