Day 16: Exceptions - String to Integer HackerRank Solution

Day 16: Exceptions - String to Integer HackerRank Solution
Source : https://www.hackerrank.com/challenges/30-exceptions-string-to-integer

Objective
Today, we're getting started with Exceptions by learning how to parse an integer from a string and print a custom error message. Check out the Tutorial tab for learning materials and an instructional video!

Task
Read a string, , and print its integer value; if cannot be converted to an integer, print Bad String.

Note: You must use the String-to-Integer and exception handling constructs built into your submission language. If you attempt to use loops/conditional statements, you will get a score.

Input Format

A single string, .

Constraints

• , where is the length of string .
• is composed of either lowercase letters () or decimal digits ().

Output Format

Print the parsed integer value of , or Bad String if cannot be converted to an integer.

Sample Input 0

3

Sample Output 0

3

Sample Input 1

za

Sample Output 1

Bad String

Explanation

Sample Case contains an integer, so it should not raise an exception when we attempt to convert it to an integer. Thus, we print the .
Sample Case does not contain any integers, so an attempt to convert it to an integer will raise an exception. Thus, our exception handler prints Bad String.

Source : https://www.hackerrank.com/challenges/30-exceptions-string-to-integer

Solution

	// Karthikalapati.blogspot.com
	import java.util.Scanner;
	public class Solution {
	public static void main(String[] args) {
	Scanner scan = new Scanner(System.in);
	String str = scan.next();
	scan.close();
	try {
	int num = Integer.parseInt(str);
	System.out.println(num);
	} catch (NumberFormatException e) {
	System.out.println("Bad String");
	}
	}
	}