Print the Elements of a Linked List HackerRank Solution

Print the Elements of a Linked List HackerRank Solution
Source : https://www.hackerrank.com/challenges/print-the-elements-of-a-linked-list

This challenge is part of a MyCodeSchool tutorial track and is accompanied by a video lesson.

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If you're new to linked lists, this is a great exercise for learning about them. Given a pointer to the head node of a linked list, print its elements in order, one element per line. If the head pointer is null (indicating the list is empty), don’t print anything.

Input Format

The first line of input contains , the number of elements in the linked list.
The next lines contain one element each, which are the elements of the linked list.

Note: Do not read any input from stdin/console. Complete the printLinkedList function in the editor below.

Constraints

• , where is the element of the linked list.

Output Format

Print the integer data for each element of the linked list to stdout/console (e.g.: using printf, cout, etc.). There should be one element per line.

Sample Input

21613

Sample Output

1613

Explanation

There are two elements in the linked list. They are represented as 16 -> 13 -> NULL. So, the printLinkedList function should print 16 and 13 each in a new line.

Source : https://www.hackerrank.com/challenges/print-the-elements-of-a-linked-list

Solution

	// Karthikalapati.blogspot.com
	/*
	Print elements of a linked list on console
	Node is defined as
	class Node {
	int data;
	Node next;
	}
	*/
	void Print(Node head) {
	Node n = head;
	while (n != null) {
	System.out.println(n.data);
	n = n.next;
	}
	}