Day 2: More Dice HackerRank Solution


Day 2: More Dice HackerRank Solution
Source : https://www.hackerrank.com/challenges/s10-mcq-2

Objective
In this challenge, we practice calculating probability. We recommend you review the previous challenge's Tutorial before attempting this problem.

Task
In a single toss of fair (evenly-weighted) six-sided dice, find the probability that the values rolled by each die will be different and the two dice have a sum of .

1 / 9
1 / 6
2 / 3
5 / 6


Source : https://www.hackerrank.com/challenges/s10-mcq-2


Solution


github.com/RodneyShag
Answer: 1/9
There are 6 possibilities on each die. On 2 dice, there are 6 * 6 = 36 possibilities
There are 4 cases that match the desired criteria: (1,5) (5,1) (2,4) (4,2)
This gives us a probability of 4/36 = 1/9

No comments:

Post a Comment