Day 21: Generics HackerRank Solution


Day 21: Generics HackerRank Solution
Source : https://www.hackerrank.com/challenges/30-generics



Source : https://www.hackerrank.com/challenges/30-generics


Solution


// Karthikalapati.blogspot.com
import java.util.*;
class Printer <T> {
/**
* Method Name: printArray
* Print each element of the generic array on a new line. Do not return anything.
* @param A generic array
**/
public void printArray(T[] array) {
for (T item : array) {
System.out.println(item);
}
}
}
public class Generics {
public static void main(String args[]){
Scanner scanner = new Scanner(System.in);
int n = scanner.nextInt();
Integer[] intArray = new Integer[n];
for (int i = 0; i < n; i++) {
intArray[i] = scanner.nextInt();
}
n = scanner.nextInt();
String[] stringArray = new String[n];
for (int i = 0; i < n; i++) {
stringArray[i] = scanner.next();
}
Printer<Integer> intPrinter = new Printer<Integer>();
Printer<String> stringPrinter = new Printer<String>();
intPrinter.printArray( intArray );
stringPrinter.printArray( stringArray );
if (Printer.class.getDeclaredMethods().length > 1) {
System.out.println("The Printer class should only have 1 method named printArray.");
}
}
}

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