Most Important Frequently Asked Caterpillar Aptitude Interview Questions
Interview Quesions on Caterpillar Aptitude
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Answer :
We are given that x=2×3×7×a=42a and y=2×2×8×b=32b
We are given that the values of both x and y lie between 120 and 130 (not including the two).
The only multiple of 42 in this range is 42×3=126.
Hence, x=126 and a=3.
The only multiple of 32 in this range is 32×4=128.
Hence, y=128 and b=4.
Hence, a-b=3-4= -1.
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Answer :
S.P = 26000 and C.P = 24700.
Profit = S.P – C.P = 26000 – 24700 = 1300
Profit percentage = (Profit /C.P) x 100 = (1300/26000) x 100 = 100 / 20 = 5 %.
Financial Planning Interview Questions -
Answer :
Total price = 12000 + 10000 = 22000
Total Cost price = Rs 22000
SP of mobile phone
=> 88 % of CP
= (88/100) x 12000
= 0.88 x 12000
= 10560
SP of refrigerator
= 108% of CP
= (108/100) x 10000
= 1.08 x 10000
= 10800
Total SP = 10560 + 10800
= 21360
Loss = (C.P.) - (S.P.)
Loss = 22000 – 21360
= 640.
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Answer :
In the given problem, let C.P denote the cost price, then
(100+9)% of CP – (100-7) % of C.P = Rs. 64
=>(109)% of CP – (93) % of C.P = Rs. 64
=>16 % of CP = 64
=> CP = 64 x 100 / 16 = 400.
Power Electronics Tutorial -
Answer :
The grocer buys rice at m Rs/Kg
Then he sells at Rs (110/100)m per 80/100 Kg Or, at Rs. 110 m /100 x (100/80) per kg = 11 m / 8 per kg
Profit = 11m/8 – m = 3m/8
Profit percentage = (3m/8) / m x (100) = 300/8 = 37.5%.
Sales Interview Questions -
Answer :
Cost of the goods be 1 Re per kg.
He sells for Re 1 what cost to him is Rs. 0.96
Gain = 1 – 0.96 = 0.04
Gain percentage = (0.04/0.96) x 100 = 25/6 %.
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Answer :
If C.P = 10 Rs. then S.P = (11/10 x 11) = 12.1 Rs
Gain = 12.1 - 10 Rs = 2.1 Rs
Gain % = profit/C.P x 100 = 2.1 / 10 x 100 = 21 %.
Electrical Engineering Interview Questions -
Answer :
Let the C.P = k Rs.
Profit = 15 % on C.P => profit = 15k/100
S.P = C.P + profit = k + 15k/100 = 115k/100
=> 115k/100 = 230 => k =230 x (100/115) = 200Rs.
Profit = 15 % on 200 Rs = 30 Rs.
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Answer :
Let the cost price be k Rs.
Profit percentage = 10%, profit = (10/100) x k = k/10
S.P = C.P + Profit = k + (k/10) = 11k/10
11k/10 = 16500 => k = 16500 x (10/11) = 15000.
Maintenance and Manufacturing Interview Questions -
Answer :
We have C.P of one dozen apple = Rs. 5,
Loss percent = 4 %
Loss = (4/100) x 5
= 1/5 Rs
S.P = C.P – Loss
= (5 – 1 / 5)
= 24 /5 Rs.
Thus S.P of one dozen apple = Rs. 24/5
S.P of one apple = (24 / 5) x (1/12)
= 2/5 Rs
= (2/5) * 100 paisa
= 40 paisa.
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Answer :
Effective cost price = Rs. 1215 + Rs. 35 = 1250
He needs 16% profit on the cost price. Profit = (16/100) x 1250 = 200
S.P = C.P + Gain = 1250 + 200 = 1450.
Insurance Interview Questions -
Answer :
L.C.M of 9 and 12 = 36
Given, C.P of 12 bananas = 9 Rs.
=> C.P of 36 bananas = 27 Rs.
Given, S.P of 9 bananas = 12 Rs
=> S.P of 36 bananas = 48 Rs.
Since S.P > C.P, there must be some profit,
Profit = S.P - C.P
= 48 - 27 = 21
Profit percentage = (profit / C.P) x 100
= (21 / 27) x 100
= 700 / 9
= 77.78%.
Financial Planning Interview Questions -
Answer :
Let the cost price of each article be Rs k
We have, S.P of 10 articles = C.P of 12 articles = 12k
We know that C.P of 10 articles = 10 k
Gain on the purchase of articles = 12 k – 10k = 2k
Profit percentage = (profit/C.P) x 100 = (2k/10k) x 100 = 20%.
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Answer :
C.P = Rs. 1500 and Profit = 20%
=> profit = (20/100) x 1500 = 300
S.P = C.P + profit
= 1500 + 300
= 1800.
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Answer :
L.C.M of 8 and 10 = 40
C.P of 10 bananas = 8 Rs => C.P of 40 bananas = 32 Rs.
S.P of 8 bananas = 10 Rs. => S.P of 40 bananas = 50 Rs.
A person buys 40 bananas for 32 Rs. and sells it for 50 Rs, it is clear that he made profit of 18 Rs.
Profit percentage = (profit/C.P) x 100 = 18/32 x 100 = 56.25%.
Power Electronics Interview Questions -
Answer :
Given
Cost price C.P = 1200 Rs,
Overhead charges = Rs. 300
Effective cost price = 1200 + 300 = 1500
Selling price = Rs. 1600
Since S.P > EffectiveC.P, there is some amount of profit
Profit = S.P – C.P
= 1600 - 1500
= 100 Rs.
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Answer :
Cost price = 3000, Profit = Rs. 300
We know that
Profit = S.P – C.P
=> S.P = Profit + C.P
= 300 + 3000
= 3300.
Marketing Interview Questions -
Answer :
Given , Labelled price = Rs. 750
Discount = 20 % of labelled price
= ( 20 / 100 ) x 750
= 2 x 75
Discount = 150
Selling Price = Labelled Price - Discount
= 750 - 150
= Rs. 600
Given , profit = 25 %
Cost Price = [100/ (100 + Gain%)] * Selling Price
= [ 100 / ( 100 + 25 ) ] * 600
= ( 100 / 125 ) * 600
= 480 Rs.
Sales Interview Questions -
Answer :
Let the List price of the article = Rs. 100
Given, Cost price(C.P) =3/4 th of the list price
= (3/4) * 100
= 75 Rs.
Given, Selling price =half more than the list price
= 1/2 of list price + list price
= (1/2) * 100 + 100
= 50 + 100
= 150 Rs.
Gain % = {(S.P - C.P) / C.P} * 100%
= {(150 - 75) / 75} * 100%
= (75/ 75) * 100%
= 100%
Thus,Gain % = 100%.
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Answer :
Solution is
Given
Let Cost Price = 100 Rs
Marked price = 30 % more than Cost Price
= 30 % of C.P + C.P
= ( ( 30 / 100 ) x 100 ) + 100
= 30 + 100
= 130 Rs
Given Discount = 10 % of marked price
= ( 10 / 100 ) x 130
= 13 Rs
Selling Price = Marked Price - Discount
= 130 - 13
=117.
Financial Services Interview Questions -
Answer :
Solution is
Given
Let the Cost price = 100 Rs
Marked price = 20 % more than the cost price
= 20 % of C.P + C.P
= ( ( 20 / 100 ) * 100 ) + 100
Marked price = 120 Rs
Discount = 10 % of marked price
= ( 10 / 100 ) * 120
= 12 Rs
Selling price = Marked price - Discount
= 120 - 12
= 108 Rs
Gain = ( Selling Price - Cost price)
= 108 - 100
= 8
%Gain = ( Gain * 100 / CP)
= (8 *100)/100
= 8%.
Gain percent = 8 %.
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Question 22. A Watch Is Bought For Rs. 1600 And Sold At A Loss Of 20 %. Find Its Selling Price?
Answer :
Given
Cost price = Rs. 1600
Loss % = 20 %
Selling price = [ (100 - Loss %) / 100 ] * C.P
= [ (100 - 20) / 100 ] * 1600
= [ 80 / 100 ] * 1600
= 80 * 16
= 1280.
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Question 23. A Table Is Bought For Rs. 1500 And Sold At A Loss Of 30 %. Find Its Selling Price?
Answer :
Solution is
Given
Cost price = Rs.1500
Loss % = 30 %
Selling price = [ ( 100 - Loss % ) / 100 ] * C.P
= [ ( 100 - 30 ) / 100 ] * 1500
= [ 70 / 100 ] * 1500
= 70 * 15
= 1050.
Diesel Mechanic Interview Questions -
Question 24. The Chair Is Bought For Rs. 1900 And Sold At Rs. 2565. Find The Profit Percent?
Answer :
Solution is
Cost Price = Rs. 1900
Selling Price = Rs. 2565
profit = selling price - cost price
Profit = Rs. 665
Profit Percentage = (Profit / C.P) x 100%
Profit Percentage = ( 665 / 1900 ) x 100
Profit Percentage = 35 %.
Electrical Engineering Interview Questions -
Question 25. The Wooden Toy Is Bought For Rs. 1600 And Sold At Rs. 1920. Find The Profit Percent?
Answer :
Cost Price = Rs. 1600
Selling Price = Rs. 1920
Profit = Rs. 320
Profit Percentage = (Profit / C.P) x 100
Profit Percentage = (320/1600) x 100
= 320 / 16
= 20%
Profit Percentage = 20 %.
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Question 26. A Notebook Is Bought For Rs. 1100 And Sold At Profit Of 5 %. Find Its Selling Price?
Answer :
Given
Cost price = Rs. 1100 Profit % = 5 %
Selling price = ( 100 + Gain % ) / 100 X CP
= (100 + 5) / (100) x 1100
= 105 / 100 x 1100
= 105 x 11
= 1155
Selling price = Rs 1155.
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Question 27. A Wooden Toy Is Bought For Rs. 1200 And Sold At Profit Of 20 %. Find Its Selling Price?
Answer :
Given
Cost price of Toy = Rs 1200
Profit or Gain = 20%
Selling price =[ ( 100 + Gain % ) / 100] * C.P
= (100 + 20 ) / 100 * 1200
= 120 / 100 * 1200
= 120 * 12
= 1440
Selling Price = Rs 1440.
Maintenance and Manufacturing Interview Questions -
Question 28. A Table Is Bought For Rs. 1783 And Sold At Profit Of 65 %. Find Its Selling Price?
Answer :
Given, Cost price = Rs. 1783
Profit % = 65 %
Selling price = [(100 + profit%) / 100] * Cost Price
=> Selling price = [(100 + 65) / 100] * 1783
= (165 / 100) * 1783
=2941.95
Thus, Selling price of Table = Rs. 2941.95.
Topic: Caterpillar Aptitude Interview Questions
Interview Quesions on Caterpillar Aptitude
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